Degrees on the miter in a hexagon

[H.Blad]

I have built a hexagonal "frame" from roughly 40cm furring strips. I managed to get the miter joints fairly well in the end, but I'm a bit curious if there isn't a specific angle to use for a hexagon.
I read up a bit on it, and it said that all the angles are 120 degrees. That would mean to miter a corner, you would use 60 degrees on each strip, but that doesn't work.
How should one think about this, does anyone know?

 

[larsbj]

the angle on the miter saw becomes (180-120)/2 that is 30 degrees

 

[larsbj]

The same applies to all angles (180-v)/2 for example 90 degrees (180-90)/2 = 45

 

[saturnus]

Oh, I always thought it was 135 degrees..................outward :2 = 67.5

 

[13th Marine]

There are 360 degrees in a full circle, if you want to make a hexagon the angles should be 360/6 = 60 degrees. To determine how to cut, you then divide by two 60/2 = 30 degrees, resulting in two 30-degree cuts (you could have a 60+0 or 45+15 if you want, but it won't look nice if there's a profile involved).

 

[H.Blad]

Thanks for the answers, it's quite obvious when you think about it a little. But sometimes you get stuck...

 

[13th Marine]

If you don't ask, you won't find out =)

 

[bax]

....one could have a 60+0 or 45+15 if desired, but it wouldn't look good if there's any profile to the whole thing....

And not only that, the outer corners wouldn't meet and a point would protrude from one of the pieces.

 

[MathiasS]

Having some difficulty with the logic in the answers above...... The angle sum is 720 degrees in a hexagon, each angle is 120 and this should be halved to get the angle for each cut. But, then it happens to be that the angle you set on the saw is the complementary angle to these 60 degrees.... Easily seen if you draw it.

But all ways are good except those that don't work....

 

[bygga_bo]

The interior angle between two sides in a regular n-gon/polygon is 180-360/n. The angle of the miter shall be half of the interior angle. The complementary angle (set on the saw) thus becomes 90-(180-360/n)/2, which can be simplified to 180/n.

So, the saw should be set to "180 divided by the number of sides in the polygon." Quite easy to remember...

 

[Mikael_L]

Now I want to see a reliable answer, this thread has been too vinklad so far ...

 

[bax]

From my perspective, 13th Marine has given the correct answer, except for the bit about different "vinkeltal".