10,157 views ·
22 replies
10k views
22 replies
Calculate the strength/load capacity of an M2.5 threaded bolt?
You're supposed to just pull the load, not lift it. And the handle is fixed on two sides.
Imagine if you actually lifted it. That would be 50 kg per side. If you were right, you should then be able to break the bolt with just your hands...
Imagine if you actually lifted it. That would be 50 kg per side. If you were right, you should then be able to break the bolt with just your hands...
It is very possible, but when I tried loading it, I notice that the bolt is by far its weakest point. There isn't a chance that it will hold. Also, my original thread isn't about more subjective assessments regarding the cart itself. What I was looking for was to technically support the argument that this part of the cart is undersized by demonstrating what a 3mm screw can actually handle in terms of weight (consider that the load is likely to exceed 100kg sideways with the leverage effect.
The cart looks flimsy, I agree, with something that looks like hard plastic wheels etc. Load it with 100Kg and drive a bit over sticks and stones. Then submit a complaint. Just make sure to document these 100Kg so there won't be any talk about you overloading it.
The screw will shear off. And it will happen in two places, right and left. There will be two screw areas that will shear off. The question is what breaks first, the screw or the fastening? If the fastening is weak, deformation can occur and thereby affect the load drop. It can become complex to calculate. Agree on thoroughly testing at maximum load.
richardtenggren
Ingen-gör
· Norrlandet
· 6 615 posts
richardtenggren
Ingen-gör
- Norrlandet
- 6,615 posts
So that can't be M3, then I should book an appointment with an optician! 
I think more like M5, but a quick overall calculation gives;
Assume that the allowable shear stress is Ttill=0.6*Rm, which gives Ttill=0.6*800 MPa if we assume 8.8 quality. As for M3 is about 5 mm3.
F=m*a => m=F/a and F=Ttill*As =>
m=Ttill*As/a= 480*5/9.82~240 kg
But you have two setups... So it should hold
I think more like M5, but a quick overall calculation gives;
Assume that the allowable shear stress is Ttill=0.6*Rm, which gives Ttill=0.6*800 MPa if we assume 8.8 quality. As for M3 is about 5 mm3.
F=m*a => m=F/a and F=Ttill*As =>
m=Ttill*As/a= 480*5/9.82~240 kg
But you have two setups... So it should hold
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