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Opening in load-bearing core wall. Can I calculate like this?
Hello everyone.
I'm calculating an opening in a load-bearing core wall made of Leca in the upcoming basement.
What I'm trying to find out is if a Leca beam is sufficient to have over an opening.
The opening is 1800 mm
The Leca beam, which is of type 200x200x2400 mm, has an allowable load for long-term deflection of 11 kN/meter
Loads per meter I've calculated like this. (CC is 600 mm on the floor above. (No roof loads go down into the core wall)
Input data:
Self-weight of the floor 0.85 kN/m2
Imposed load on the floor 2.5 kN/m2 (kitchen/living room without interior walls)
Load per beam kN/meter: (NOTE unit)
From self-weight 0.6x0.85 = 0.51 kN/meter
From imposed load 0.6x2.5 = 1.5 kN/meter
Total load 1.5+0.51 = 2.01 kN/meter
The beam can handle 11kN/meter at a span of 1800 mm
Then I should be really safe. With a factor over 5
IF one can calculate as I have done?
This is where you come in.
Comments? Have I calculated correctly?
Thanks!
I'm calculating an opening in a load-bearing core wall made of Leca in the upcoming basement.
What I'm trying to find out is if a Leca beam is sufficient to have over an opening.
The opening is 1800 mm
The Leca beam, which is of type 200x200x2400 mm, has an allowable load for long-term deflection of 11 kN/meter
Loads per meter I've calculated like this. (CC is 600 mm on the floor above. (No roof loads go down into the core wall)
Input data:
Self-weight of the floor 0.85 kN/m2
Imposed load on the floor 2.5 kN/m2 (kitchen/living room without interior walls)
Load per beam kN/meter: (NOTE unit)
From self-weight 0.6x0.85 = 0.51 kN/meter
From imposed load 0.6x2.5 = 1.5 kN/meter
Total load 1.5+0.51 = 2.01 kN/meter
The beam can handle 11kN/meter at a span of 1800 mm
Then I should be really safe. With a factor over 5
IF one can calculate as I have done?
This is where you come in.
Comments? Have I calculated correctly?
Thanks!
Hello
You calculated an aspect of 3 and believe it is wrong, and without an image, it becomes difficult. I am attaching a simple sketch on how to transfer a surface to a beam.View attachment ladda upp.pdf
The total load becomes the surface, in my case 3x1.8 = 5.4 sqm. The load on the beam is fixed + live load.
Fixed is about 50kg/m2 and live about 200kg/m2, which gives 2.5kN/m2 and times the surface becomes 2.5 x 5.4 = 13.5 kN.
When you have all the loads, you release the beam and apply the loads you have.
I threw some values into a calculation program for wooden beams, and if you have a glulam 115x180, you utilize it to 36%. So compare your leca beam with a glulam in bending strength.View attachment ladda upp.pdf
Then your supports must withstand about 1.2 tons each, and what the supports stand on must withstand a part.
Hope that helped a bit.
You calculated an aspect of 3 and believe it is wrong, and without an image, it becomes difficult. I am attaching a simple sketch on how to transfer a surface to a beam.View attachment ladda upp.pdf
The total load becomes the surface, in my case 3x1.8 = 5.4 sqm. The load on the beam is fixed + live load.
Fixed is about 50kg/m2 and live about 200kg/m2, which gives 2.5kN/m2 and times the surface becomes 2.5 x 5.4 = 13.5 kN.
When you have all the loads, you release the beam and apply the loads you have.
I threw some values into a calculation program for wooden beams, and if you have a glulam 115x180, you utilize it to 36%. So compare your leca beam with a glulam in bending strength.View attachment ladda upp.pdf
Then your supports must withstand about 1.2 tons each, and what the supports stand on must withstand a part.
Hope that helped a bit.
Thank you so much for the example! Afraid it wasn't as simple as my way of calculating 
I'll review your calculation and recalculate with a sketch.
Thanks!
I'll review your calculation and recalculate with a sketch.
Thanks!
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