This thread is for a comrade who is going to remove a load-bearing wall. A structural engineer will be contacted before the renovation starts, but you can never have too much meat on the bones, as the fat girl said.

The existing joist for the upper floor is 250mm in wood. Below this is tongue and groove and after that, fabric with an air gap of 50mm.

The idea is to remove the load-bearing wall and replace it with a beam, and in turn, completely remove the beam so that it's not visible. The idea is to use a steel beam since you can reduce the height.

But how do you attach the joists to the steel beam?

One idea: Fill the space in the H-beam (HEA or similar) with glulam on each side. This glulam is fastened with bolts and nuts M10. Then the beam becomes square, and you attach joist hangers to the wood for the joists.

A functioning construction? This means you have to drill 10mm holes in the steel beam.

Add thoughts and ideas.
 
Shoot fast joist hangers onto the steel beam with a bolt gun.
 
I just pressed the beam flush against the wood. The joist framework is well cross-braced so it's not going anywhere.
 
It may not have been clear, but we don't want the beam under the joist; the idea is to cut it flush with the joist.

Here is an image made by me to illustrate my idea.
What is then added are joist hangers to secure the cut joist to the beam/wood. Illustration of a wooden beam aligned with floor joists, showing cut joists within the beam. Beam shoes suggested for securing structure.

Objections?
 
Someone could calculate this;

In a quick phone contact with a designer, it was said that if we choose a steel beam of type HEA, there should be no problem with one about 200mm in height.

Would someone kindly calculate how high an IPE beam would be instead.
Simply put, can an HEA 200 be replaced with an IPE 200/220/240/260?
Length about 6 meters.

This is to reduce the width that must be filled with wood, as well as the weight, and thereby the price.
 
You can calculate that yourself - search for HEA and IPE and you will find tables with section modulus Z - find a matching IPE beam (same or higher Z).

Otherwise, the solution you have drawn should work. Carriage bolt and square nut s=1200 or something like that, but the designer needs to look at it - you need to ensure the beam shoes can handle the load as well - you haven't specified any support length?
 
Why not skip the joist hangers entirely and place the studs directly on the beam, possibly with a horizontal stud to raise it to the appropriate height?

Sent from my GT-I9100 using Byggahus
 
It will probably be difficult to get it there then - the floor and the joists are already in place as I understand it.
 
Matti_75 said:
Shoot the joist hangers onto the steel beam with a powder-actuated tool.
Or rather: ask a carpenter with a permit for the powder-actuated tool to do it. ;)
 
Johan Gunverth said:
Or rather: ask a carpenter with permission for a bolt gun to do it. ;)
There are bolt guns today that do not require training, only powder-actuated ones require it. Today, there are gas and air pressure-driven guns.
 
Matti_75 said:
There are bolt guns today that don't require training, it's only powder-driven ones that require it. Nowadays there are gas and air pressure-driven guns.
Aha, thanks! Good to know. The last time I asked was 5-6 years ago and only powder was available for the purpose and I couldn't rent. Solved it with the carpenter in the family.
 
Locke said:
Will probably be difficult to put there then - the floor and joists are already in place as I understand.
Exactly.

The length between the columns and thus the beam is about 6 meters.
 
But how long is the joist on both sides of the beam? It is that load that the beam should handle.
 
Locke said:
But how long is the floor structure on both sides of the beam? It's that load the beam should handle.
It's the upper floor's flooring that needs to be supported, possibly some snow load through the kneewalls as well.
Approximately 3.5m floor structure on each side of the beam.
 
Yes, it's becoming a bit of a burden. It's probably good for someone to calculate that.
 
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