Right angle

[Daniel-GBG]

What is the formula to determine the correct angle given exact measurements?

For example:

Side A 8606mm
Side B 11006
Side C ?????

 

[Daniel_N]

What is the formula to calculate a right angle from exact measurements?

Like

Side A 8606mm
Side B 11006
Side C ?????

(a^2)+(b^2)=c^2

8606^2+11006^2=c^2

74063236+121132036=c^2

c^2 = 195195272

c= square root(195195272)

c= approx. 13971.2

 

[titanium]

Tips: http://hem.ektv.nu/~ekt000851/trigo.html

 

[Fredrik.engdahl]

why make it so difficult

take the standing one 6000, the lying one 8000, and then the one that goes from the lying to the standing 10,000

 

[Larsa]

Just like Fredrik writes, the formula is 3x4x5 for a right-angled triangle. Then you can multiply this to suitable dimensions for the current case 30x40x50, 60x80x100...

 

[bygga_bo]

Daniel_N doesn't make it difficult... what you (Fredrik and Larsa) bring up is a special case where the sides have a ratio of 3-4-5 (also known as an Egyptian triangle). That is not the case with Daniel-GBG's triangle.

 

[bigsnucke]

As a math teacher, I can't help but agree with the above, but I'm a bit curious; what are you going to measure that is more than 11 meters where you need to use tenths of a mm? (Are you going to build the world's largest machine angle?...)

 

[Sailorman]

As a math teacher, I can only agree with the above, but I am a bit curious; what are you going to measure that is more than 11 meters and where you need to use tenths of a mm? (Are you going to build the world's largest machine angle?...)

Yes, the thing with the number of significant figures can be interesting...

 

[blackadder]

would have been interesting to know how you managed to get such precise measurements over such a long distance.

Laser?