I have encountered a problem with calculating the U-value for different parts of a basement wall above and below ground. Here is how it looks:

The following construction from the outside:
Morain
Fiber cloth
200 mm draining material
100 mm EPS insulation, λ = 0.033 W/mK
200 mm concrete, λ = 1.7 W/mK

Above ground, the EPS insulation is plastered with 20 mm plaster; λ = 1.0 W/mK

See image!!

Can someone help me?
 
  • Cross-section diagram of a basement wall construction showing layers of moraine, fiber cloth, drainage material, cellular plastic, and concrete with measurements.
surris
O ogsaboster said:
I have encountered a problem with calculating the U-value for different parts of a basement wall above ground and below ground. It looks like this:

The following construction from the outside:
Morän
Fiberduk
200 mm draining material
100 mm celloplast, λ = 0.033 W/mK
200 mm concrete, λ = 1.7 W/mK

Above ground, the celloplast is plastered with 20 mm plaster; λ = 1.0 W/mK

See image!!

Can anyone help me?
0.30 W/m2,K above and 0.25 below ground W/m2,K.
 
Thank you for the response. But how did you calculate it? This is driving me crazy. I just can't figure it out at all.
 

Best answer

surris
O ogsaboster said:
Thanks for the reply. But how did you calculate it? I'm going crazy over this. I can't figure it out at all.
First, you need to calculate the thermal resistance of the different layers, which you do by taking the thickness (in meters) of the material divided by the lambda value. For external, internal, and ground conditions like your basement wall, there is a European standard for thermal resistance. Once calculated, add everything and divide by 1. For example, your basement wall above ground.

Rtot=Rse+Riso+Rbet+Rsi (R stands for thermal resistance)

0.04+(0.1/0.033)+(0.2/1.7)+0.13=3.3

U=1/Rtot

1/3.3=0.30 W/m2,K.

If it's not homogeneous layers, then you calculate it a bit differently.
 
Thank you so much!!!
 
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surris
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