Hello!

I've attempted to build a triangular raised bed and want to cut the boards so I can assemble them with the end grain against each other. It's become apparent that geometry is not my strong suit; how should I approach this?

The plan is to have the dimensions 2550x1900x1900mm and I've calculated the degrees that the angles should be, but I'm struggling with that when I try to cut. The angles end up too wide, preventing the triangle from "forming."

My thought was that you'd calculate the angle in a corner, divide it by two, and then cut both ends at that angle against each other. Am I thinking totally wrong?
 
Hello!

Do the angles in the image match the ones you use?

Triangle with angles A=47.852°, B=47.852°, C=84.297° and sides a=1,900, b=1,900, c=2,550.
 
Yes, so I cut at angle A and B with 24 degrees "inward" so that the end grain would meet.
 
These are untrimmed parts, but here I trimmed the red-marked parts at 24 degrees on the miter saw and it didn't turn out well as I described in the post.
 
  • Two wooden boards with marked sections and uneven cuts from a 24-degree miter saw angle, as discussed in the post.
From the little I remember from mathematics, it would have worked to halve the angles if it were an equilateral triangle. 180/3=60/2=30
Now one side is longer and the angle needs to be divided perpendicularly to the opposite side. I'll see if I can find an image that shows this better.
 

Best answer

Your angles A+B are 180-~49= 131*/2=65.5* so you should cut to get it right
 
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Ronny Johansson6 and 1 other
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Ah okay, is that how you're supposed to calculate. Thanks!

Follow-up question then, if your miter saw can only be angled to 60 degrees. What do you do then?
 
You can use a template that is 45 degrees, for example. And then set the saw to 20.5 degrees.

 
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Qvint
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Both of your tips worked super well, thank you so much for the help!
 
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Matti_75
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