I have a load-bearing beam 145x70 on my patio roof. The beam length is 4m. The roof is 4m wide and approximately 5-5.5m deep from the house facade. The roof is flat with a parapet and about a 15-degree slope. I want to "notch out" the beams that run from the house facade outward (145x45mm) to recess the steel and then install a ceiling panel so that no beams are visible. My question is, what dimension of steel is required to replace the existing 145x70mm beam? Grateful for an answer from a professional!
Don't understand. What are you trying to do? Do you want to increase the ceiling height or what's the deal?
There is a right way forward. You contact a structural engineer and get this calculated with paperwork and everything, make a building notification, and then everything is done correctly.
There is a right way forward. You contact a structural engineer and get this calculated with paperwork and everything, make a building notification, and then everything is done correctly.
I don't want a visible load-bearing beam. I want to replace it with a smaller square steel like 50x50 or similar that I can recess under the other beams that extend from the house facade supporting the conservatory roof. I want to make notches in these beams from underneath and recess the steel.Den ofrivillige klåparen said:
Aha. Let an engineer take a look at that, you are also altering the longitudinal beams, there's likely some shear where you want to notch out.F freyan said:
There are no screws where I want to notch, only attached at the outer edges as far as I can see.Den ofrivillige klåparen said:
This beam lies under all the others and supports in the middle so there won't be any sagging on the roof, and you should be able to walk on it without risk of collapse, etc.
I was hoping there would be a qualified engineer who could give a qualified tip 😀
Shear, not screw!F freyan said:
There are plenty of competent people on this forum, but doing structural calculations is time-consuming and cognitively demanding. The most qualified thread I've seen on the subject was actually yesterday, where someone wanted to lift a given mass in a beam cross-section - which is covered in the very first chapters of an introductory course in strength of materials. Never otherwise have I seen anyone calculate either stiffness or stress. If you get someone to do this for you for free, congratulations, but what often happens (if anyone even answers) is that you get a bunch of guesses (masked as certain answers), which are not worth anything in practice.
Ok, I guess I'll check with a constructor who can help me.Den ofrivillige klåparen said:Shear, not screw!
There is plenty of competent people on this forum, but doing structural calculations is time-consuming and cognitively demanding. The most qualified thread I've seen on the subject was actually yesterday, where someone wanted to lift a given mass in a beam cross-section - which is covered in the very first chapters of an introductory course in strength of materials. Never otherwise have I seen anyone calculate either stiffness or stresses. If you get someone to do this for free, congratulations, but what usually happens (if anyone even answers) is that there will be a lot of guesses (masked as seemingly accurate answers), but they are not worth anything in practice.
Thanks for your posts.
Ps. What is Sjuv?🤔
I've never heard that word before. Excuse my ignorance 😏
I would have done it anyway! Fingers crossed someone comes here to help you, but my hopes are not sky-high.F freyan said:
Shear is a bit of a sloppy expression, I should have written shear force or shear stress. It's a term used to describe force/stress in a body, see the image below which probably explains it better than if I wrote a novel here.
By the way, I may have misunderstood what you want to do, difficult with text.
It helps a lot with a sketch.